Find a point on the x axis which is equidistant from the point 7,6and

1.	Find a point on the x axis which is equidistant from the point 7,6and -3,4
Answer» Any point P on x axis is of the form of (x,0). Lwe A=(7,6) and B =(-3,4)It is given that PA= PB√(7-x)2\xa0+(6-0)2\xa0= √(-3-x)2\xa0+ (4-0)2√(7-x)2\xa0+(6)2\xa0= √(-3-x)2+(4)2√49+x2\xa0-14x+36 = √9+x2\xa0+16+6x√x2\xa0-14x+85= √x2+6x+25Squaring both sides , we getx2-14x+85= x2\xa0+6x +25-14x-6x = 25-85-20x = -60x = 3So point P = (3,0)\xa0

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