Saved Bookmarks
| 1. |
Find a quadratic polynomial whose zeros are (3+√5) and (3-√5) |
| Answer» Let, alpha =3+√5 & Bitta =3-√5Sum of the zeros (alpha+bitta) = 3+√5 + 3-√5 = 3+3 =6Product of the zeros (alpha×bitta) = 3+√5 × 3-√5 = (3)^2 - (√5)^2 = 9 - 5 = 4So, the required quadratic polynomial is (x^2 -(alpha+bitta)x + (alpha ×Bitta)x^2 - (6)x + (4)x^2 - 6x + 4 | |