1.

Find a quadratic polynomial whose zeros are -3,2

Answer» Let, Alpha= -3 & Bitta = 2 Sum of the zeros =(alpha + Bitta) = -3 + 2 = -1Product of the zeros = (alpha × Bitta) = -3 × 2 = -6So,the required quadratic polynomial is x^2 -(alpha + bitta)x +(alpha × bitta) x^2 -( -1 )x + ( -6 ) x^2 + x -6
alpha=-3 &bita= 2Alpha +bita= -3 + 2= -1Alpha*bita=-3*2=-6x2-( alpha+ bita)x + alpha* bita = x2 -(-1)x +6 =x2 +x +6


Discussion

No Comment Found