1.

Find a two digits number, the sum of its digits is 14 and when the digits are interchanged their places the obtained number is 18 less than the original number.1. 862. 683. 954. 59

Answer» Correct Answer - Option 1 : 86

Given:

The sum of digits is 14 and the number is 21 less when the digits are reversed

Calculation:

Let the once place digit is y and tens place digit is x

∴ The number is = 10x + y

Now, the sum of digits is 14

∴ x + y = 14     --- (1)

And the number is 21 less when the digits are reversed

∴ 10x + y = x + 10y + 18

⇒ x - y = 2      --- (2)

By equation (1) and (2)

∴ x = 8 and y = 6

Hence number = 86.


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