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Find area of the triangle whose vertices are (2,4),(_1,0)(2,_4)

Answer» {tex}\\begin{array}{l}\\left(2,3\\right),\\;\\left(-1,0\\right),\\;\\left(2,-4\\right)\\\\Area\\;of\\;Triangle\\;=\\;\\frac12\\left[2\\;\\left(0+4\\right)\\;+\\left(-1\\right)\\left(\\;-4-3\\right)+2\\left(3-0\\right)\\right]\\end{array}{/tex}{tex}( 2,3 ) , ( - 1,0 ) , ( 2 , - 4 ){/tex}Area of Triangle\xa0{tex}= \\frac { 1 } { 2 } [ 2 ( 0 + 4 ) + ( - 1 ) ( - 4 - 3 ) + 2 ( 3 - 0 ) ]{/tex}{tex}= \\frac{1}{2}(8 + 7 + 6){/tex}{tex}= \\frac{{21}}{2}{/tex} square units.


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