Find arithmetic progression whose third term is 16 and the seventh term exceeds the 5 th term by 12

Find arithmetic progression whose third term is 16 and the seventh ter

1.	Find arithmetic progression whose third term is 16 and the seventh term exceeds the 5 th term by 12
Answer» a3 = 16{tex} \\Rightarrow {/tex}\xa0a + 2d = 16 ..... (i)a7 = a5 + 12{tex} \\Rightarrow {/tex}\xa0a + 6d = a + 4d + 12{tex} \\Rightarrow {/tex}\xa02d = 12{tex} \\Rightarrow {/tex}\xa0d = 6Put the value of d in eq. (i){tex}a + 2 \\times 6 = 16{/tex}{tex} \\Rightarrow {/tex}\xa0a = 16 - 12{tex} \\Rightarrow {/tex}\xa0a = 44, 10, 16....