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Find \(\frac{dy}{dx}|_{x=\frac{\pi}{2}}\) , where y = esin x. |
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Answer» We have, y = esin x ⇒ \(\frac{dy}{dx}=e^{sinx} .cosx\) ∴ \(\frac{dy}{dx}|_\frac{\pi}{2}=e^1 .0=0\) |
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