1.

Find \(\frac{dy}{dx}|_{x=\frac{\pi}{2}}\) , where y = esin x.

Answer»

We have,

y = esin x

⇒ \(\frac{dy}{dx}=e^{sinx} .cosx\)

∴ \(\frac{dy}{dx}|_\frac{\pi}{2}=e^1 .0=0\)



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