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Find HCF of 65 and 117 and express it in the form 65m + 117n |
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Answer» HCF = 1313 = 65m + 117nFrom [ 1] ,13 = 65 - 52 x 1From [2] ,52 = 117 - 65 x 1 ----> [3]Hence ,13 = 65 - [ 117 - 65 x 1 ] ------> from [3]= 65 x 2 - 117= 65 x 2 + 117 x [-1 ]m = 2n = -1 HCF = 1313 = 65m + 117nFrom [ 1] ,13 = 65 - 52 x 1From [2] ,52 = 117 - 65 x 1 ----> [3]Hence ,13 = 65 - [ 117 - 65 x 1 ] ------> from [3]= 65 x 2 - 117= 65 x 2 + 117 x [-1 ]m = 2n = -1Read more on Brainly.in - https://brainly.in/question/1192640#readmore |
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