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Find hcf of the number given below:- k,2k,3k,4k and 5k. Where k is a positive integers

Answer» {tex}\\begin{array}{l}k=\\;k\\times1\\\\2k=\\;k\\times2\\\\3k=k\\times3\\\\4k=k\\times2\\times2\\\\5k=k\\times5\\end{array}{/tex}Here k is a positive integerHence HCF(k,2k,3k,4k,5k)=\xa0k.


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