find k for real roots 2x²+kx+3=0

1.	find k for real roots 2x²+kx+3=0
Answer» Here, a=2, b=k, c=3D=b^2-4ac/2a =k^2-4×2×3/2×2=K^2-24/4=0 k^2=24K=√24.......It may helpful to you. We have to find the values of\xa0k\xa0for quadratic equations 2x² + kx + 3 = 0 so that they have two\xa0equal\xa0roots.we know, quadratic equation will be equal only whendiscriminant, D = b² - 4ac = 0on comparing 2x² + kx + 3 = 0 with general form of quadratic equation , ax² + bx + c = 0 we get, a = 2, b = k and c = 3so Discriminant , D = (k)² - 4(2)(3) = 0or, k² - 24 = 0or, k = ± √24 = ±2√6hence, the value of k =\xa02√6 or -2√6

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