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Find K if kx (x-3)+8=0 has real and equal roots |
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Answer» Kx²-3x+8=0Given condition : real and equal rootsie.,D=0 or b²-4ac =0a=k, b=-3kc=8b²-4ac=0[(-3k)² - 4ac]=0[9k²-32k] =09k²-32k=09k²=32k9k*k=32kK=32k/9kk=32/9or k=3.555..... approximately: 3.6 X=12 therefore k=6 |
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