Find K if the sum of the zeroes of the polynomial x^2-(K+6)x+2(2K-1) is half of their product

Find K if the sum of the zeroes of the polynomial x^2-(K+6)x+2(2K-1) i

1.	Find K if the sum of the zeroes of the polynomial x^2-(K+6)x+2(2K-1) is half of their product
Answer» Given quadratic polynomial, x² - (k+6)x + 2(2k+1) = 0By comparing it with ax²+bx+c = 0,we geta = 1 , b = -(k+6) , c = 2(2k+1)Sum of zeroes = -b/a= -[-(k+6)]/1= k+6Product of zeroes = c/a= 2(2k+1)/1= 2(2k+1)Now..... Sum of zeroes = ½ × product of zeroes k+6 = ½ × 2(2k+1)k+6 = 2k+12k-k = 6-1k = 5Hope it helps Plz plz..... Answer fast guys it\'s urgent