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| 1. |
Find pairs of natural numbers whose least common multiple is 78 and the greatest divisor is 13 |
| Answer» Least common factor (LCM) = 78Greatest divisor is also a HCF = 13As, we know , HCF {tex}\\times{/tex} LCM = a {tex}\\times{/tex} b ( a and b are two natural no. of which LCM and HCF is given)Therefore, required product of no. = 13 {tex}\\times{/tex} 78 = a {tex}\\times{/tex} b =1014 or 2{tex}\\times{/tex}3{tex}\\times{/tex}13{tex}\\times{/tex}13Since 13 is common in both no. as its HCF is 13Required no.= 13{tex}\\times{/tex}3 = 39 and 13 {tex}\\times{/tex}2 = 26{tex}\\therefore{/tex}\xa0Pairs of natural numbers are 78 and 13 or 26 and 39. | |