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| 1. |
Find roots if 3x2+2x+3=0 |
| Answer» We have,3x2\xa0+ 2x + 3Here, a = 3, b = 2 and c = 3{tex}\\therefore{/tex}\xa0{tex}D = b^2 - 4ac{/tex}= (2)2 - 4 {tex}\\times 3 \\times 3{/tex}= 4 - 36= 32 > 0{tex}\\therefore{/tex}\xa0D >\xa00So, the given equation has real and distinct roots. | |