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| 1. |
Find smallest number which leaves reminders 8and 12 when divided by 28 and 32 respectively |
| Answer» The LCM of 28 and 3228 = 2× 2 × 7=22×732 = 2 × 2 × 2 × 2 × 2=25LCM = 25 × 7 = 224Smallest no: which leaves remainder 8 and 12 when divided by 28 and 32= LCM of 8 & 12 = 224 - 20 = 204Therefore, 204 is smallest number which when divided by 28 and 32 leaves remainder 8 and 12 respectively. | |