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| 1. |
Find sum of first 8 multiples of 3. Ch arithmetic progression |
| Answer» The first 8 multiples of 3 are : 3, 6, 9, 12, 15, 18, 21, 24Number of terms = 8The first term = a1 = 3The last term = a8 = 24Find the sum:Sn = n/2 ( a1 + an)S8 = 8/2 (3 + 24)S8 = 108Hence the sum of the first 8 multiples of 3 is 108. | |