Find the 10 th term of the AP whose sum of n term is given by 2n^2 +3n

1.	Find the 10 th term of the AP whose sum of n term is given by 2n^2 +3n
Answer» ANSWERS n\u200b =2n 2 +3nWe know that nth term of AP is given bya n\u200b =S n\u200b −S n−1\u200b ⟹a n\u200b =2n 2 +3n−2(n−1) 2 −3(n−1)⟹a n\u200b =4n+1Tenth term=a 10\u200b =4×10+1⟹a 10\u200b =41 A=S1= 2×1^2+3×1=5A2 = S2-S1 =( 2×2^2+3×2)-5=14-5=9 ..........d=a2 - a1 = 9-5=4a10= a + (n-1)d........5+(10-1)×4.........5+9×4=5+36=41 A10 =41 Sn=2n²+3n, we know An=Sn-Sn-1(n is at foot and - 1 is from n)....... A10 =S10 - S9........ A10 =2×10²+3×10 - 2×9-3×9........... An=200+30-18-27........ An=185

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