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Find the 11th term from the last term of AP 27,23,19,.....,-65 |
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Answer» 27 , 23 , 19 ,...., - 65 is an A.Pa = 27 ,common difference = a2 - a1d = 23 - 27 = - 4Rewrite the A..P,- 65, - 61, - 57, ... 19, 23, 27here,first term = a = - 65common difference = a2 - a1d = - 61 - ( - 65 )d = -61 + 65d = 4n = 11nth term = an = a + ( n - 1 )da11 = -65 + ( 11 - 1 ) 4= -65 + ( 10 {tex}\\times{/tex} 4 )= -65 + 40= -25Therefore,required 11th term= a11 = - 25 -65,-61,-57.....27a=-65.d=4N=11An=a +(n-1)dA11=-65+(11-1)4-65+40=-2511th term is -25 |
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