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Find the 18th term of AP: √2,√18,√50,√98,... |
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Answer» Ap= √2,√18,√50, √98 it can also be writtenin the form Ap=√2,3√2,5√2,7√2...... A=√2. D=2√2. Now, a of 18= a+( n-1 )×d. √2+17×2√2. = √2+34√2. =35√2 answer.? Ap is in form /2, 3/2, 5/2 ........ where / means root and difference d = a2-a1 =3/2-/2 = 2/2 a=/2d=2/2a18= a+17d = /2 + 17×2/2 = /2 + 34/2 =35/2 = /2450 The AP can be written as:√2 ,3 √2 ,5 √2 ,7 √2 ...a= √2 and d=2 √2a18= √2 +17*2 √2=(1+34) √2=35 √2 ={tex}\\sqrt 2450{/tex}\xa0 35√2 A=root 2D=2 root2N=18Therefore applying a+(n-1)dANSWER IS= 35root2 35 root 2..... sqrt 2450 |
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