Saved Bookmarks
| 1. |
Find the 2 consecutive odd positive integer sum of whoose square is 290 |
|
Answer» Let one odd integer be XThen the other will be (X+2)their sum of squares = x² +(x+2)² = x² + x² + 4x +4 = 2x² + 4x + 4Given that their sum of squares = 290 2x² +4x + 4 = 290 2x² +4x = 290-4 = 2862x² + 4x -286 = 0 2(x² + 2x - 143) = 0 x² + 2x - 143 = 0 x² + 13x - 11x -143 = 0 x(x+13) - 11(x+13) = 0 (x-11) , (x+13) = 0 x = 11 or -13So integers are 11 n 13 11 And 13 |
|