Saved Bookmarks
| 1. |
find the all of the zeros |
| Answer» Given polynomial is x4 + x3 - 34x2 - 4x + 120Since, the two zeroes of the polynomial given is 2 and -2So, factors are (x + 2)(x - 2) = x2 + 2x - 2x - 4 = x2 - 4dividend = divisor × quotient + remainderdividend= x4 + x3 - 34x2 - 4x + 120divisor = x2 - 4quotient = x2 + x - 30remainder = 0So, x4 + x3 - 34x2 - 4x + 120 = (x2 - 4)(x2 + x - 30)= (x - 2)(x + 2)(x2 + 6x - 5x - 30)= (x - 2)(x + 2)(x + 6)(x - 5)Therefore, the zeroes of the polynomial = x = 2, -2, -6, 5 | |