Find the Angle subtended at the center of a circle of radius 5cm by an

1.	Find the Angle subtended at the center of a circle of radius 5cm by an arc of length (5π/3)cm.
Answer» Radius of circle = 5cmLength of arc\xa0{tex} = \\frac{{5\\pi }}{3}cm{/tex}{tex}\\therefore {/tex}\xa0length of arc\xa0{tex} = \\frac{\\theta }{{360^\\circ }} \\times 2\\pi r{/tex}{tex} \\Rightarrow \\frac{{5\\pi }}{3} = \\frac{\\theta }{{360^\\circ }} \\times 2\\pi \\times 5{/tex}{tex} \\Rightarrow \\theta = \\frac{{5\\pi \\times 360^\\circ }}{{3 \\times 2\\pi \\times 5}}{/tex}{tex} \\Rightarrow \\theta = 60^\\circ {/tex}

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