Find the area of a quadarant of a Circle whose circumference 22cm

1.	Find the area of a quadarant of a Circle whose circumference 22cm
Answer» ????????????? = ???? ?π? = ?? 2 x 22/7 x r = 22 r = 22 x 7/2 x 22 ? = ?/?In quadrant, angle of sector, = 90°Area of the quadrant = 90°/360° × πr^2 = 40 × 22/7 × 7/2 × 7/2 = 1540 cm^2ᎻᎾᏢᎬ ᎷᎽ ᎯᏁᏕᏯᎬᏒ ᏯᎨᏝᏝ ᏰᎬ ᎻᎬᏝᏢƒυℓℓ Circumference= 2×22/7×r22=2×22/7×rr=22×7/2×22r=7/2=3.5 cmArea of quadrant= 1/4×22/7×7/2×7/2 =77/8cm² Formulas used =\xa01. Circumference = 2 pie r2. Area of Quadrant = 1/4 Pie r²Circumference = 2 Pie r 22 = 2 * 22/7 r r = 22 * 7 / 22 * 2r = 7/2 or 3.5 cmArea Of Quadrant = 1/4 Pie r² = (1/4) * (22/7 ) * 3.5 * 3.5 = 1 * 22 * 35 * 35 / 4 * 7 * 10 * 10 = 1 * 11 * 35 / 4 * 10= 9.625 cm²\xa0

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