InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Find the area of a quadrant of a circle whose circumference is 44cm |
| Answer» Circumferences of a circle\xa0{tex}= 2 \\pi r{/tex}{tex}\\Rightarrow 2 \\pi r = 44{/tex}{tex}\\Rightarrow 2 \\times \\frac { 22 } { 7 } \\times r = 44{/tex}{tex}\\Rightarrow{/tex}\xa0r = 7 cm{tex}\\therefore{/tex}\xa0Area of the quadrant{tex}= \\left( \\frac { 1 } { 4 } \\times \\frac { 22 } { 7 } \\times 7 \\times 7 \\right) \\mathrm { cm } ^ { 2 }{/tex}{tex}= \\frac { 77 } { 2 } \\mathrm { cm } ^ { 2 }{/tex}{tex}= 38.5 cm^2{/tex} | |