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Find the area of minor segment of circle of radius 42 cm. If length of corresponding arc is 44cm. |
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Answer» Length of arc = θ/360 2πr = 44 cmPutting r = 42cm, we get θ= 60°Now, Area of minor segment= Area of minor sector-Area of ∆Since = 60°, so the triangle formed will be an equilateral∴ ∆ Area of minor segment= Area of minor sector - Area of equilateral ∆i.e. Area of minor segment = θ/360 πr2 -\xa0√3/4 a2= 924 - 441√3 cm2 76 approx |
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