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Find the area of quadrant of a circle whose circumference is 22 cm |
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Answer» Circumference of circle = 22 2πr = 22 2× 22/7 ×r = 22 r= 7/2Area of quadrant = theta/ 360 ×πr2 90/360× 22/7 × 7/2 ×7/2 = 77/8 |
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