Saved Bookmarks
| 1. |
Find the area of quadrant of a circle whose circumferenceis 22 cm |
| Answer» Let the radius of the circle be r cm.Then, circumference\xa0of the circle = 2{tex}\\pi{/tex}r cmAccording to the question,2{tex}\\pi{/tex}r = 22{tex}\\Rightarrow 2 \\times \\frac { 22 } { 7 } \\times \\mathrm { r } = 22{/tex}{tex}\\Rightarrow \\mathrm { r } = \\frac { 22 \\times 7 } { 2 \\times 22 } \\Rightarrow \\mathrm { r } = \\frac { 7 } { 2 } \\mathrm { cm }{/tex}For a quadrant of a circle,{tex}= \\frac { \\theta } { 360 } \\times \\pi r ^ { 2 }{/tex}{tex}= \\frac { 90 } { 360 } \\times \\frac { 22 } { 7 } \\times \\left( \\frac { 7 } { 2 } \\right) ^ { 2 }{/tex}{tex}= \\frac { 90 } { 360 } \\times \\frac { 22 } { 7 } \\times \\frac { 7 } { 2 } \\times \\frac { 7 } { 2 } = \\frac { 77 } { 8 } \\mathrm { cm } ^ { 2 }{/tex} | |