Find the area of quadrilateral ABCD in which AB=3cm BC=4cm. CD=4cm. DA

1.	Find the area of quadrilateral ABCD in which AB=3cm BC=4cm. CD=4cm. DA =5cm and AC =5cm
Answer» For ΔABCa = 4 cmb = 5 cmc = 3 cm∵ a2\xa0+ c2\xa0= b2\xa0∴ ΔABC is right angled with ∠B = 90°.∴ Area of right triangle ABC\xa0For ΔACDa = 4 cm b = 5 cmc = 5 cm\xa0∴ Area of the ΔACD= 2 x 4.6 cm2\xa0(approx.)= 9.2 cm2\xa0(approx.)∴ Area of the quadrilateral ABCD= Area of ΔABC + Area of ΔACD= 6 cm2\xa0+ 9.2 cm2= 15.2 cm2, (approx.)

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