Find the area of rhombus each side of which measures 40cm and one of whose diagonal is 48cm.

Find the area of rhombus each side of which measures 40cm and one of w

1.	Find the area of rhombus each side of which measures 40cm and one of whose diagonal is 48cm.
Answer» Diagonals of Rhombus bisect each other 48×1/2=24cmDiagonals of Rhombus bisect each other at right angle By Pythagoras theorem = 24^2 + AO^2 = 40^2 =576+ AO^2 =1600 =AO^2=. 1600-576= 1024=√1024=32cmD1=48cm (given)D2=32x2=64cm Area of Rhombus=1/2 x D1 x D2=1/2x48x64= 1536