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Find the area of rhombus of vertices (3,0),(4,5),(-1,4)&(-2,-1)taken in order

Answer» Thankx
suppose the vertices are A,B,C,D IN SEQUENCE THENAC2=16+16=32 HENCE AC= (32)1/2BD2=36+36=72 HENCE BD= (72)1/2AREA OF RHOHMBUS=1/2*AC*BD=48 Cm\xa0sqr
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