Find the area of the segment AYB ,if radius of the cricle is 21 cm and

1.	Find the area of the segment AYB ,if radius of the cricle is 21 cm and ∆AOB =120. (π= 22/7)
Answer» 461 Lgta hai aap hi merried mein aayge In ∆AOB, draw a perpendicular line from O which intersect AB at M.In ∆AOM, angle AMO = 90angle OAM = 30cos 30 = AM/AO√3/2 = AM/21AM = 21×√3/2AB = 2(AM)=2(21×√3/2)=21√3{tex}OM^2 = AO^2-AM^2{/tex}{tex}=21^2-(21√3/2)^2{/tex}=441-330.51=110.48OM =√110.48OM =10.51OM = 10.51cmArea of ∆AOM = 1/2 AB × OM=1/2 ×21√3 ×10.51=191.14cm^2Area of sector AOBY = 120πr^2/360=120×21×21×22/2520=462cm^2Area of segment AYB = Area of sector OAYB -Area of∆OAB=462-191.14=270.86Area of segment AYB is 270.86cm2.\xa0

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