Find the area of the shaded region .if pq=24 cm ,pr =7 cm and 0 is the centre of the circle .

Find the area of the shaded region .if pq=24 cm ,pr =7 cm and 0 is the

1.	Find the area of the shaded region .if pq=24 cm ,pr =7 cm and 0 is the centre of the circle .
Answer» Given,PQ=24cmPR=7cmO is the center of circleTo find shaded regionIn ∆PQRar(PQR)=1/2×PR×PQ1/2×24×7=84cm^2we know that RQ is the hypotenuse of ∆PQR and diameter of the circlethen,To find RQRQ^2=PR^2+PQ^2RQ^2=24^2+7^2RQ^2=576+49RQ^2=625RQ=√625RQ=25cmarea of circle semicircle,1/2πr^21/2π×(24)^2by solving using the value od π we get 6875/28Area of shaded region= Area of semicircle- Area of tirange pqr6875/28-84=4532/28ans where is the figure?