1.

Find the area of the triangle whose vertices are: P(0, 0), Q(6, 0) and R(4, 3)

Answer»

Area of a triangle = \(\frac{1}{2}\)\(\begin{bmatrix} x_1 & y_1 & 1 \\[0.3em] x_2 & y_2 & 1 \\[0.3em] x_3 &y_3 & 1 \end{bmatrix}\)

\(\frac{1}{2}\)\(\begin{bmatrix} 0 & 0& 1 \\[0.3em] 6 & 0 & 1 \\[0.3em] 4 &3& 1 \end{bmatrix}\)

Expanding with R1

\(\frac{1}{2}[18]\)

= 9 sq. units



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