Find the area of triangle whose vertices are : (1). (2,3), (-1,0), (2,

1.	Find the area of triangle whose vertices are : (1). (2,3), (-1,0), (2,-4)
Answer» Let\xa0A(2,3),\xa0B(−1,0)\xa0and\xa0C(2,−4)\xa0are the vertices of\xa0△ABCArea of triangle= 1/2 \u200b[x1\u200b(y2\u200b−y3\u200b)+x2\u200b(y3\u200b−y1\u200b)+x3\u200b(y1\u200b−y2\u200b)]Here\xa0(x1\u200b,y1\u200b)=(2,3)(x2\u200b,y2\u200b)=(−1,0)(x3\u200b,y3\u200b)=(2,−4)= 1/2 \u200b[2(0+4)−1(−4−3)+2(3−0)]= 1/2 \u200b[8+7+6]= 21/2 \u200b\xa0sq.unit

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