1.

Find the co-ordinate of focus, and length of latus rectum of parabola 3y2 = 8x

Answer»

Given equation of the parabola is 

3y2 = 8x

\(=y^2=\frac{8}{3}x\\=y^2=4.\frac{2}{3}x\)

Here, a = \(\frac{2}{3}\)

∴ focus = (a, 0) = ( \(\frac{2}{3}\) , 0)

And length of latus rectum = 4a = \(\frac{8}{3}\)



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