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Find the co-ordinate of focus, and length of latus rectum of parabola 3y2 = 8x |
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Answer» Given equation of the parabola is 3y2 = 8x \(=y^2=\frac{8}{3}x\\=y^2=4.\frac{2}{3}x\) Here, a = \(\frac{2}{3}\) ∴ focus = (a, 0) = ( \(\frac{2}{3}\) , 0) And length of latus rectum = 4a = \(\frac{8}{3}\) |
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