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Find the common difference if 17th term of an A.P exceeds its 10th term by 14 |
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Answer» A/Q,a+16d-a-9d=14. or, 7d=14 or,d=2 Let a be the first term and d the common difference.It is given a_{17} - a_{10} = 7⇒ (a + 16d) - (a + 9d) = 7⇒ 7d = 7 ⇒ d = 1 d=2 |
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