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Find the coordinates of the point which divides the join of (-1,7) and (-4,3) in the ratio 2:3. |
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Answer» Let the co ordinate of the point (x,y)x={tex}mx2+nx1\\over m+n{/tex}={tex}2\\times(-4)+3\\times(-1)\\over2+3{/tex}={tex}-8-3\\over5{/tex}={tex}-11\\over5{/tex}y={tex}my2+ny1\\over m+n{/tex}={tex}2\\times3+3\\times7\\over2+3{/tex}={tex}6+21\\over5{/tex}={tex}27\\over5{/tex}The coordinate of the point is ({tex}-11\\over5{/tex},{tex}27\\over5{/tex}) (-1,7) (-4,3)√(-4+1)+(3+7)√(-3)+(4)√1 |
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