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Find the cubic polynomial whose zeroes are 2-7 and -14 respectively

Answer» Let the cubic polynomial be ax3 + bx2 +cx + dand its zeroes be\xa0{tex}\\alpha ,\\beta {/tex}\xa0and\xa0{tex}\\gamma{/tex}.Then,\xa0{tex}\\alpha + \\beta + \\gamma= 2 = \\frac { - b } { a }{/tex}{tex}\\alpha \\beta + \\beta \\gamma + \\gamma \\alpha = - 7 = \\frac { C } { a }{/tex}and\xa0{tex}\\alpha \\beta \\gamma = - 14 = \\frac { - d } { a }{/tex}If a = 1, then b = -2, c = -7, d = 14So, one cubic polynomial which fits the givenconditions is x3 - 2x2 - 7x + 14.


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