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Find the distance of (-4,3) from y axis.

Answer» The point on the y-axis is (-4,3){tex}\\therefore {/tex}Distance between (-4,3) and (0,3)d =\xa0{tex}\\sqrt { ( 0 + 4 ) ^ { 2 } + ( 3 - 3 ) ^ { 2 } }{/tex}=\xa0{tex}\\sqrt { 16 + 0 }{/tex}= 4\xa0units


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