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Find the distance of a point (x;y) from the origin.does anyone have an answer . |
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Answer» As we were asked to find out distance. So distance must be specified with some measurements or units; otherwise it remains absurd. So the word \'units\' must be written. The coordinates of origin is(0,0).The coordinates of the given point is (x,y) .Now, By applying distance formula, we get; Required distance of the given point from origin =√{(x-0)² +(y-0)²} =√(x²+y²) units Let point be p(x,y) and origin O(0,0).So, distance (PO)=√(0-x)^2+(0-y)^2 PO=√x^2+y^2. And. X+Y The coordinates of origin is (0,0) and the coordinates of given point is (x,y) . So by applying distance formula = root under hole (x-0)square + (y-0) square = root under hole x square + y square Under root(x-0)2+(y-0)2 = under root X2+y2 Please elaborate Under root X square + Y square Square root of (x sq. and y sq.) |
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