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Find the distance of the point (-13, 4) from the equation of the line 20x + 21y + 2 = 0?1. 4 unit 2. 5 unit 3. 6 unit4. 7 unit |
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Answer» Correct Answer - Option 3 : 6 unit Given: A point(-13, 4) is given and the equation of the line 20x + 21y + 2 = 0. Formula Used: Distance (d) = |(Ax1 + By1 + C)/(√(A2 + B2)| Where Ax + By + C is the given equation of the line, and (x1,y1) is the given point from where the distance is calculated. Calculation: By using the above formula we get ⇒ Distance (d) = |(20 × -13 + 21 × 4 + 2)/√(202 + 212)| ⇒ d = |(-260 + 86)/ 29| = 174/29 ∴ Distance is 6 unit. |
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