1.

Find the distance of the point (-13, 4) from the equation of the line 20x + 21y + 2 = 0?1. 4 unit 2. 5 unit 3. 6 unit4. 7 unit

Answer» Correct Answer - Option 3 : 6 unit

Given:

A point(-13, 4) is given and the equation of the line 20x + 21y + 2 = 0.

Formula Used:

Distance (d) = |(Ax1 + By1 + C)/(√(A2 + B2)|

Where Ax + By + C is the given equation of the line, and (x1,y1) is the given point from where the distance is calculated.

Calculation:

By using the above formula we get

⇒ Distance (d) = |(20 × -13 + 21 × 4 + 2)/√(202 + 212)|

⇒ d = |(-260 + 86)/ 29| = 174/29

∴ Distance is 6 unit.   



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