Find the eleventh term from the last tera of the AP:27,23,19,....-56.

1.	Find the eleventh term from the last tera of the AP:27,23,19,....-56.
Answer» Write the above A.P. in reverse order , we get\xa0-56,-52,-48..............a= -56 d= 4a11\xa0= a+(n-1)da11\xa0= -56+(11-1)4a11\xa0= 56+104a11\xa0= -56+40a11 = -16 An = A + (n-1)DA= -56D= -4A11 = -56 + ( 11-1 ) -4A11 = -56 + (10) -4A11 = - 56 - 40A11 = - 96 -96

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