1.

Find the equation of the line passing through the point (–1, 6) and slope = 3.1. y = 3x + 62. 3y = x + 93. y = 3x + 94. y = 3x – 1

Answer» Correct Answer - Option 3 : y = 3x + 9

Given:

Point (–1, 6)

Slope = 3

Formula Used:

Equation of a line in slope form

y = mx + C

m = slope , C = constant

Calculation:

Equation of line y = 3x + C 

For the value of C, point (–1, 6) will satisfy the equation

⇒ 6 = 3(–1) + C 

⇒ C = 6 + 3 

⇒ C = 9

Now, the equation of line is y = 3x + 9

∴ The equation of the line passing through the point (–1, 6) and slope 3 is y = 3x + 9



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