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1. |
Find the free electron concentration in ionsphere if its refractive index is equal to `n = 0.90` for radiowaves of frequency `v = 100 MHz`. |
Answer» From the previous problem `n^(2) = 1-(n_(0)e^(2))/(epsilon_(0) momega^(2))` `=1 - (n_(0)e^(2))/(4pi^(2)epsilon_(0)mv^(2))` Thus `n_(0) = (4pi^(2)v^(2)m epsilon_(0)//e^(2)) (1-n^(2)) = 2.36 xx 10^(7)cm^(-3)` |
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