1.

Find the free electron concentration in ionsphere if its refractive index is equal to `n = 0.90` for radiowaves of frequency `v = 100 MHz`.

Answer» From the previous problem
`n^(2) = 1-(n_(0)e^(2))/(epsilon_(0) momega^(2))`
`=1 - (n_(0)e^(2))/(4pi^(2)epsilon_(0)mv^(2))`
Thus `n_(0) = (4pi^(2)v^(2)m epsilon_(0)//e^(2)) (1-n^(2)) = 2.36 xx 10^(7)cm^(-3)`


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