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find the greatest number of 6 digits exactly divisible by 18,24 and 36 |
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Answer» Solution: First find the LCM of all the given numbers. LCM ( 18, 24, 36 ) = 72Now the greatest 6-digit number is 99,99,99.Thus, 99,99,99\xa0/ 72\xa0=\xa0{tex}\\large13888 \\frac 78 \\sim13888{/tex}and 13888\xa0x 72\xa0= 99,99,36.which is our required answer. The answer is = 999936 |
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