Saved Bookmarks
| 1. |
Find the greatest number of 6 digits exactly divisible by 18, 24 and 36 |
|
Answer» No mention, Kajal. Thanku Chapter 1 in hindi LCM (18, 24, 36) = 72. Largest number of 6 digits = 999999. Dividing 999999 by 72, we get a remainder 63. Therefore, the greatest number of 6 digits exactly divisible by 18, 24, 36 is 999999 - 63 = 999936// |
|