Find the greatest number of six digits exactly divisible by 18,24 and

1.	Find the greatest number of six digits exactly divisible by 18,24 and 36
Answer» LCM of 18,24 and 3618 = 2 {tex}\\times{/tex}\xa03224 = 23{tex}\\times{/tex}\xa0336 = 22{tex}\\times{/tex}\xa032LCM (18,24,36) = 23\xa0{tex}\\times{/tex}\xa032 = 72Hence if any number is divisible by 72 that will be divisible by 18,24 and 36 also.Now the largest 6 digit number is 999999On dividing 999999 by 72 we get{tex}\\;999999=13888\\times72+\\;63=999936+63{/tex}Hence 999936 is the greatest 6 digit number divisible by 18,24 and 36.

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