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Find the greatest number which divides 285 and 1249 leaving remainder 9 and 7 respectively |
| Answer» The required number when divides 285 and 1249, leaves remainder 9 and 7, this means285 - 9 = 276 and 1249 -7 = 1242 are completely divisible by the number.Therefore, the required number = H.C.F. of 276 and 1242.By applying Euclid’s division lemma,1242 = 276 {tex}\\times{/tex}\xa04 + 138276 = 138 {tex}\\times{/tex}\xa02 + 0.Therefore, H.C.F. = 138Hence, The greatest number which divides 285 and 1249 leaving remainder 9 and 7 respectively is 138. | |