Find the hcf and lcm of 11008 and 7344 using fundamental of arithmetic

1.	Find the hcf and lcm of 11008 and 7344 using fundamental of arithmetic
Answer» The prime factorization of 11008 is2\|110082\|55042\|27522\|13762\|6882\|3442\|1722\|8643\|43111008=2×2×2×2×2×2×2×2×4311008=2 × 8×43The prime factorization of 7344 is2\|73442\|36722\|18362\|9183\|4593\|1533\|5117\|1717344=2×2×2×2×3×3×3×177344=2 × 4×3 × 3×17Now, HCF=Product of the smallest power of each commonprime factor in the numbers.HCF=2 × 4=16LCM = Product of the greatest power of each prime factor,involved in the numbers.LCM=2 × 8×43×3 × 3×17=256×43×27×17=5052672 Hello See ncert book Hi

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