Saved Bookmarks
| 1. |
Find the HCF of 36,96,120 |
|
Answer» 36=2×2×3×396=2×2×2×2×2×3120=2×2×2×3×5Therefore HCF(36,96,120)=2×2×3=12 By Euclid\'s division lemma on 36 and 96a=bq+r , where r is equal to or greater than 0 and smaller than bSince 96 is greater than 36Therefore a= 96 and b= 36Now, 96=36×2+24 36=24×1+12 24=12×2+0Since 12 is the last divisore therefore 12 is HCF of 36 and 96Now, we will take HCF of 12 and 120By Euclid\'s division lemmaa=bq+r, where r is equal to or greater than 0 and smaller than bSince 120 is greater than 12 Therefore a= 120 and b= 12Now, 120=12×10+0Since 12 is the last divisore therefore 12 is HCF of 12 and 120.Therefore HCF of 120,96 and 36 is 12 On applying euclid\'s division Lemma for 36 and 9696 = 36 ×2 + 24Here, Remainder = 24≠0So take new Dividend as 36 and divisor as 24.36 = 24×1 +12Here, Remainder = 12≠0So take new Dividend as 24 and divisor as 12.24 = 12×2 +0Here, the Remainder = 0 and the last divisor is 12.So, HCF of 36 and 96 is 12.On applying euclid\'s division Lemma for 12 and 120120 = 12 ×10 + 0Here Remainder = 0So , HCF of 36, 96 and 120 is 12. |
|